Home
Class 12
PHYSICS
Two bodies are throw at angle theta (90...

Two bodies are throw at angle `theta` (90-`theta`) from the same point with same velocity `25 ms^(-1)`. If the difference between their maximum height is 15m. Find the respective maximum heights. (`g = 10ms^(-2)`).

A

`185/8` m and `65/8` m

B

`125/4`m and `65/4` m

C

40 m and 25 m

D

25 m and 40 m

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Two bodies are thrown at angles theta and (90- theta ) from the same point with same velocity 25ms^(-1) . If the difference between their maximum heights is 15m, the respective maximum heights are (g=10 ms^(-2) )

A particle is projected at an angle theta =30^@ with the horizontal, with a velocity of 10ms^(-1) . Then

Two bodies are projected at angle theta and ( 90 -theta ) to the horizontal with the same speed. Find the ration of their time of flight.

A ball is thrown at angle theta and another ball is thrown at an angle (90^(@)-theta) with the horizontal direction from the same point with velocity 39.2 ms^(-1) . The second ball reaches 50 m higher than the first ball. Find their individual heights. Take g = 9.8 ms^(-2) .

Two balls are projected at an angle theta and (90^(@) - theta) to the horizontal with the same speed. The ratio of their maximum vertical heights is

Two bodies are thrown with the same initial velocity at angles theta and (90^@ - theta) respectively with the horizontal, then their maximum height are in the ratio

A body is projected at angle 30° to the horizontal with a velocity 50 ms^(-1) maximum height of projectile is

For a projectile, the ratio of maximum height reached to the square of flight time is (g = 10 ms^(-2))

A body is projected from the ground with a velocity v = (3hati +10 hatj)ms^(-1) . The maximum height attained and the range of the body respectively are (given g = 10 ms^(-2))

A body is projected at an angle 30° with a velocity 42 ms^(-1) Its maximum height is