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Two light waves having the same waveleng...

Two light waves having the same wavelengths `lambda` in vacuum are in phase initially . Then the first wave travels a path `L_1` through a medium of refractive index `n_1` while the second wave travels a path of length `L_2` through a medium of refractive index `n_2` . After this the phase difference between the two waves is :

A

`(2pi)/(lambda)(L_(1) - L_(2))`

B

`(2pi)/(lambda)(mu_(1)L_(1) - mu_(2)L_(2))`

C

`(2pi)/(lambda)(mu_(2)L_(1) - mu_(1)L_(2))`

D

`(2pi)/(lambda)[(Li)/(mu_(1)) - (L_(2))/(mu_(2))]`

Text Solution

Verified by Experts

The correct Answer is:
C
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