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A 75kg man stands in a lift. What force ...

A 75kg man stands in a lift. What force does the floor exert on him when the elevator starts moving upward with an acceleration of `2 ms^(-2)` Given: g = `10 ms^(-2)`.

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To solve the problem of finding the force exerted by the floor on a 75 kg man in an elevator accelerating upwards at `2 m/s²`, we can follow these steps: ### Step 1: Identify the forces acting on the man When the elevator is moving upwards, two main forces act on the man: 1. The gravitational force (weight) acting downwards, which is given by \( F_g = mg \). 2. The normal force (the force exerted by the floor on the man), which acts upwards. ### Step 2: Calculate the weight of the man ...
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