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A piece of uniform string hangs vertical...

A piece of uniform string hangs vertically so that its free end just touches horizontal surface of a table. The upper end of the string is now released. Show that at any instant during the falling of string, the total force on the surface is three times the weight of that part of string lying on the surface.

Text Solution

AI Generated Solution

To solve the problem, we need to analyze the forces acting on the string and the table as the string falls. Let's break down the solution step by step. ### Step 1: Define the Variables Let: - \( L \) = total length of the string - \( m \) = mass per unit length of the string - \( g \) = acceleration due to gravity - \( x \) = length of the string that has fallen and is now lying on the table ...
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