Discuss how apparent weight of a person in a lift changes when it is (a) moving up with acceleration (b) moving down with acceleration less than acceleration due to gravity (c) moving with uniform velocity (d) when it is stationary.

How does the weight of a person standing in a lift change when the lift accelerates (a) upwards (b) downwards with an acceleration a ?

When you move from equator to pole, the value of acceleration due to gravity (g) :-

The apparent weight of a man in a lift is w_1 when lift moves upwards with some acceleration and is w_2 when it is accelerating down with same acceleration. Find the true weight of the man and acceleration of lift.

Find the period of oscillation of a pendulum of length l if its point of suspension is (a) moving vertically up with acceleration a (b) moving vertically down with acceleration a(lt g) (c) failing freely under gravity moving horizontal with acceleration a .

The apparent weight of a man in a lift is W_(1) when lift moves upwards with some acceleration and is W_(2) when it is accerating down with same acceleration. Find the true weight of the man and acceleration of lift .

The ratio of the weight of a man in a stationary lift and when it is moving downward with uniform acceleration ‘ a ’ is 3 : 2 . The value of ‘ a ’ is ( g - Acceleration due to gravity of the earth)

A simple pendulum of length l is suspended through the ceiling of an elevator. Find the time period of small oscillations if the elevator a. is going up with an acceleration a_0 . b. is going down with an acceleration a_0 and c. is moving with a uniform velocity.

A man in a lift feels an apparent weight W when the lift is moving up with a uniform acceleration of 1/3rd of the acceleration due to gravity. If the same man were in the same lift now moving down with a uniform acceleration that is 1/2 of the acceleration due to gravity, then his apparent weight is

A lift is moving up with an acceleration of 3.675 m//sec_(2) . The weight of a man-

The apparent weight of man inside a lift moving up with certain acceleration is 900N. When the lift is coming down with the same acceleration apparent weight is found to be 300N. The mass of the man is (g = 10 ms^(-2) )