An experiment measured quantity a, b, c and then x is calculated from `x = ab^(2)//c^(3)`. If the percentage error in a, b, c are `pm` 1%, `pm` 3% and `pm` 2% respectively, the percentage error in x can be,

Explanation

Here
`(Deltaa)/(a) xx100 = pm 1 % (Deltab)/(b) xx100 = pm 3 % (Deltac)/(c ) xx100 =pm 2%`
`x = (ab^(2))/(c^(3))`
Maximum percentage error in x is
`(Deltax)/(x) xx100=(Deltaa)/(a) xx100+2(Deltab)/(b)xx100+3(Deltac)/(c )xx100`
`1+(2xx3)+(3xx2)=13%`
Maximum percentage error in x is 13%