Home
Class 12
PHYSICS
Two resistors of resistances R1 = 100 pm...

Two resistors of resistances `R_1 = 100 pm 3` ohm and `R_2 = 200 pm 4 ` ohm are connected (a) in series , (b) in parrallel. Find the equivalent resistance of the (a) series combination , (b) parallel combination . Use for (a) the relation `R = R_1 + R_2 and ` for (b) `1/R = 1/(R_1) + 1/(R_2) and (DeltaR')/(R^(,2)) = (DeltaR_1)/(R_1^2) + (DeltaR_2)/(R_2^2)`

Text Solution

AI Generated Solution

To solve the problem of finding the equivalent resistance of two resistors \( R_1 = 100 \pm 3 \) ohm and \( R_2 = 200 \pm 4 \) ohm connected in series and parallel, we will follow these steps: ### Step 1: Calculate the Equivalent Resistance in Series The formula for the equivalent resistance \( R \) in series is given by: \[ R = R_1 + R_2 ...
Promotional Banner

Topper's Solved these Questions

  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise EXERCISE -1 A|187 Videos
  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise EXERCISE- 1 B|28 Videos
  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|7 Videos
  • UNITS AND MEASUREMENT

    AAKASH SERIES|Exercise PRACTICE EXERCISE|45 Videos
  • WAVE MOTION

    AAKASH SERIES|Exercise PRACTICE SHEET ADVANCED (INTEGER TYPE QUESTIONS)|10 Videos

Similar Questions

Explore conceptually related problems

Two resistors of resistances R_(1)=100 pm 3 ohm and R_(2)=200 pm 4 ohm are connected (a) in series, (b) in parallel. Find the equivalent resistance of the (a) series combination, (b) parallel combination. Use for (a) the relation R=R_(1)+R_(2) and for (b) 1/(R')=1/R_(1)+1/R_(2) and (Delta R')/R'^(2)=(Delta R_(1))/R_(1)^(2)+(Delta R_(2))/R_(2)^(2)

Two resistances R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega are connected in series . Find the equivalent resistance of the series combination.

Two resistances R_(1) = 100 +- 3 Omega and R_(2) = 200 +- 4 Omega are connected in series . Find the equivalent resistance of the series combination.

Two resistors of resistances R_(1)=(300+-3) Omega and R_(2)=(500+-4) Omega are connected in series. The equivalent resistance of the series combination is

Two resistors of resistance R_(1) and R_(2) having R_(1) gt R_(2) are connected in parallel. For equivalent resistance R, the correct statement is

Two resistors of resistance R_(1) and R_(2) having R_(1) gt R_(2) are connected in parallel. For equivalent resistance R, the correct statement is

Two resistors of resistance R_1 = 2 Omega and R_2= 1 Omega are connected in parallel with a current source of 3 A. Draw the arrangement and deduce the current I_1" in "R_1 and I_2" in "R_2.

Two resistors of resistance R_1 = 2 Omega and R_2= 1 Omega are connected in parallel with a current source of 3 A. Draw the arrangement and deduce the current I_1" in "R_1 and I_2" in "R_2.

Write the expressions for the equivalent resistance R of three resistors R_1, R_2 , and R_3 joined in (a) parallel, and (b) series.

For two resistors R_1 and R_2 , connected in parallel, find the relative error in their equivalent resistance. if R_1=(50 pm2)Omega and R_2=(100 pm 3) Omega .

AAKASH SERIES-UNITS AND MEASUREMENTS-PROBLEM
  1. The percentage errors in the measurement of mass and speed are 2% and ...

    Text Solution

    |

  2. The error in the measurement of the length of a simple pendulum is 0.1...

    Text Solution

    |

  3. Two resistors of resistances R1 = 100 pm 3 ohm and R2 = 200 pm 4 ohm ...

    Text Solution

    |

  4. The heat dissipated in a resistance can be obtained by the measurement...

    Text Solution

    |

  5. The period of oscillation of a simple pendulum is T = 2pisqrt(L/g). Me...

    Text Solution

    |

  6. Write down the number of significant figure in the 6.032

    Text Solution

    |

  7. 20.96 rounded off to 3 significant figures is

    Text Solution

    |

  8. A stick has a length of 12.132 cm and another stick has a length of 12...

    Text Solution

    |

  9. Find the value of 2.2 + 4.08 + 3.125 + 6.3755.

    Text Solution

    |

  10. Solve with due regard to significant figures. (i) 46.7 - 10.4 = " ...

    Text Solution

    |

  11. Find the product of 1.2, 2.54 and 3.257 with due regard to significant...

    Text Solution

    |

  12. Enthalpy change of a reaction with be equal to

    Text Solution

    |

  13. A substance having mass 5.74 g occupies a volume of 1.2cm^3. Caluclate...

    Text Solution

    |

  14. Find out the results of the following operations. (i) 117.3 xx 0.002...

    Text Solution

    |

  15. If a circular piece of tin has a measured radius of 2.6 cm . What is c...

    Text Solution

    |

  16. The diameter of a sphere is 4.24 m . Calculate its surface area with d...

    Text Solution

    |

  17. Each side of a cube is measured to be 7.203 m. what are the total surf...

    Text Solution

    |

  18. The length and breadth of a rectangular sheet are 16.2 cm and 10.1 cm...

    Text Solution

    |

  19. Convert 1 newton (SI unit of force) into dyne (CGS unit of force)

    Text Solution

    |

  20. Convert the unit of work done from MKS system to CGS system (i.e. joul...

    Text Solution

    |