A substance having mass 5.74 g occupies a volume of `1.2cm^3.` Caluclate its density with due regard to significant digits.

Explanation

Mass m =5.74 g, volume v, = 1.2 `cm^(3)`
density d=`(m)/(v)= (5.74g)/(1.2cm^(3))`
5.74 has significant digits and 1.2 has two significant digits . No need for rounding off.
`:. D = (5.74)/(1.2)= 4.783333.`
This is to be rounded off to two significant digits . The density of the given substance is 4.783 = `4.8 g cm^(-3)`