Find out the results of the following operations.
`(i) 117.3 xx 0.0024 " " (ii) 9.27 div 41`
`(iii) 42 xx 0.041 " " (iv) 124.2 + 52.487`
`(v) 124.2 - 52.487 " " (vi) sqrt(58.97)`
`(vii) (17.5)^(2)`.

Explanation

(i) 0.0024 has 2 significant figures. Hence 117.3 is rounded off to have 2+ 1 = 3 significant figures. It becomes 117 only.
Now `117 xx0.0024 = 0.2808 `
This is to be rounded off to have two significant figures only. The result is 0.28.
(ii) 41 has only 2 significant digits. Hence 9.27 can have 2+1 3 significant digits. It has 3 significant dig its only. No need for rounding off.
`(9.27)/(41) = 0.2260975`
This is to be rounded off to two significant digits.
The result is 0.23.
(iii) Both number have two significant digits. 42x0.041 =1.722. This is to be rounded off to 2 signifi- cant digits . The result is 1.7.
(iv) As this is a sum, we have to consider decimal places. 124.2 has only one decimal place. Hence 52.487 is to be rounded off to 1+1 =2 deci- mal places.
It becomes as 52.487 = 52.49
Now 124.2 + 52.49 = 176.69 .
This is to be rounded off to one decimal place. The result is as 176 .69 = 176.7.
(v ) Here again we have
124.2 52.487 = 124.5249 = 71.71
This is to be rounded off to one decimal place
The result is 71.7
(vi) `sqrt(58.97)=7.679` .
This has got the same number of significant digits (4) as 58.97 .
(vii) `(17.5)&(2)=306.25` . The original number 17.5 has only 3 significant digits. And hence the result will be 306 (Here we have to consider the significant figures),.