Convert 1 newton (SI unit of force) into dyne (CGS unit of force)

Explanation

Dimensional formula of force is `M^(1)L^(1)T^(2)`
IN = n dynes `implies n =N` /dynes
`:. n_(2)=n_(1)[(M_(1))/(M_(2))]^(1)[(L_(1))/(L_(2))]^(1)[(T_(1))/(T_(2))]^(-2)`
`implies n = [(1 kg)/(1g)][(1m)/(1 cm)]^(1)[(1s)/(1s)]^(-2)((n^(2))/(n_(1))=n)`
`impliesn=[(1000g)/(1g)][(100cm)/(1cm)]^(1)[(1s)/(1s)]^(-2)`
`implies n = [1000]xx[100]^(1)xx[1]^(2)=10^(7)`
`:.` newton = `10^(7)` dynes
Alternate Method : [F] = `[MLT^(-2)]`
newton =1 (kg) (m) `(s)^(-2)`
`= 1xx(10^(3)g)(10^(2)cm ) (s)^(-2)= 10^(5)(g) (cm ) (s)^(-2)`
1 newton = ` 10^(5)` dynes