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While measuring the acceleration due to gravity by a simple pendulum, a student makes a positive error of 1% in the length of the pendulum and a negative error of 3% in the value and a of time period. His percentage error in the measurement of g by the relation `g = 4pi^(2)(l//T^(2))` will be

A

0.02

B

0.04

C

0.07

D

0.1

Text Solution

Verified by Experts

The correct Answer is:
C
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