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A vector sqrt(3)hati + hatj rotates abo...

A vector `sqrt(3)hati + hatj` rotates about its tail through an angle `30^(@)` in clock wise direction then the new vector is

Text Solution

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The magnitude of `sqrt(3)hati+hatj` is `sqrt(3+1)=2` the angle made by the vector with x-axis is
`"tan" theta=(A_(y))/(A_(x))=(1)/(sqrt(3))`
`:. theta=30^(@)`

When the given vector rotates 30 in clock wise its direction changes along x - axis but its magnitude does not change.
`:.` The new vetor is `2hati`
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