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Two vectors vecA and vecB have equal mag...

Two vectors `vecA` and `vecB` have equal magnitudes. The magnitude of `(vecA+vecB)` is n times the magnitude of `(vecA-vecB)`. The angle between `vecA` and `vecB` is :

Text Solution

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`|vecA+vecB|=n|vecA-vecB|`
`2A "cos"(theta)/(2)=n2A "sin"(A=B)`
`:. "tan" (theta)/(2)=(1)/(2), (theta)/(2)= tan^(-1)((1)/(n)), theta= 2tan^(-1)((1)/(n))`
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