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The celing of a long hall is 25 m high, ...

The celing of a long hall is 25 m high, What is the maximum horizontal distance that a ball thrown with a speed of `40ms^(-1)` can go without hitting the ceiling of the hall?

Text Solution

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Here `H=20 m, u=40 ms^(-1)`. Suppose the ball is thrown at an angle `theta` with the horizontal.
Now `H=(u^(2) sin^(2) theta)/(2g) rArr 20=((40)^(2) sin^(2) theta)/(2xx10)`
or `sin theta=0.5 " " or theta=30^(@)`
Now `R=(u^(2)sin 2 theta)/(g)=((40)^(2)xx sin 120^(@))/(10)`
`=((40)^(2)xx0.866)/(10)=138.56 cm`
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