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When two bodies approach each other with...

When two bodies approach each other with the different speeds, the distance between them decreases by 120 m for every one minute. If they are moving in direction, the distance between them increases by 90 m for very one minute. The speeds of the bodies are

A

`2ms^(-1)and0.5ms^(-1)`

B

`3ms^(-1)and2ms^(-1)`

C

`1.75ms^(-1)and0.25ms^(-1)`

D

`2.5ms^(-1)and0.5ms^(-1)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the speeds of two bodies based on their relative motion. Here’s a step-by-step solution: ### Step 1: Understand the Problem We have two cases: 1. When the two bodies approach each other, the distance between them decreases by 120 m in one minute. 2. When they move in the same direction, the distance between them increases by 90 m in one minute. ### Step 2: Set Up the Equations Let: - \( v_1 \) = speed of the first body (in m/s) - \( v_2 \) = speed of the second body (in m/s) **Case 1: Approaching Each Other** When the bodies are approaching each other, their speeds add up. The equation for this case is: \[ v_1 + v_2 = \frac{120 \text{ m}}{1 \text{ min}} = \frac{120 \text{ m}}{60 \text{ s}} = 2 \text{ m/s} \] **Case 2: Moving in the Same Direction** When the bodies are moving in the same direction, the relative speed is the difference of their speeds. The equation for this case is: \[ v_1 - v_2 = \frac{90 \text{ m}}{1 \text{ min}} = \frac{90 \text{ m}}{60 \text{ s}} = 1.5 \text{ m/s} \] ### Step 3: Solve the System of Equations Now we have a system of two equations: 1. \( v_1 + v_2 = 2 \) (Equation 1) 2. \( v_1 - v_2 = 1.5 \) (Equation 2) We can solve these equations by adding them together: \[ (v_1 + v_2) + (v_1 - v_2) = 2 + 1.5 \] This simplifies to: \[ 2v_1 = 3.5 \implies v_1 = \frac{3.5}{2} = 1.75 \text{ m/s} \] ### Step 4: Find \( v_2 \) Now, substitute \( v_1 \) back into Equation 1 to find \( v_2 \): \[ 1.75 + v_2 = 2 \implies v_2 = 2 - 1.75 = 0.25 \text{ m/s} \] ### Step 5: Conclusion The speeds of the two bodies are: - \( v_1 = 1.75 \text{ m/s} \) - \( v_2 = 0.25 \text{ m/s} \) ### Final Answer The speeds of the bodies are 1.75 m/s and 0.25 m/s. ---
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