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A particle is projected from the ground ...

A particle is projected from the ground with an initial speed u at an angle `theta` with the horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is

A

`(v)/(2)sqrt(1+2cos^(2)theta)`

B

`(v)/(2)sqrt(1+2sin^(2)theta)`

C

`(v)/(2)sqrt(1+3cos^(2)theta)`

D

`vcostheta`

Text Solution

Verified by Experts

The correct Answer is:
C
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