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A very fleible uniform chain of mass M a...

A very fleible uniform chain of mass M and length L is suspended vertically such that its lower end just touches the surface of a table. When the upper end of the chain is released . it falls with each link coming to test the instant it strikes the table.

Text Solution

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Since chain is uniform , the mass of y part of chain will be `(M/Ly)`
when this part reaches the table, its total force exerted must be equal toweight of y part resting on table + Force due to momentum imparted
`=M/L y_(g) ((M/Ldy)sqrt(2gy))/(dt) = (Mg)/L y + M/L v. sqrt(2gy)`
`(as(dy)/(dt) =v) = (Mg)/L y + M/L sqrt(2gy). sqrt(2gy) = 3(Mg)/L g`
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