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An isolated particle of mass m is moving...

An isolated particle of mass `m` is moving in horizontal plane` xy` along the `x`-axis, at a certain height above the ground. It suddenly explodes into two fragment of masses `m//4` and `3m//4`. An instant later, the smaller fragment is at `y=+15` cm. The larger fragment at this instant is at

Text Solution

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As `vecF_(y)=0, DeltavecP_(y)=0, vecP_(y) = vecP_(yf)`

`vecP_(yi) =0, therefore m_(i) vecV_(y) + m_(2) vecV_(y2)=0, m_(1)vecy_(1) =-m_(2)vecy_(2)`
`y_(2) =-(m/4 xx 15)/(3m//4), y_(2) = -5 cm`
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