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A body of mass 10 kg lies on a rough hor...

A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of `5 m//s^(2)`. And when the horizontal force is doubled, it gets an acceleration of `18 m//s^(2)`. The coefficient of friction between the body and the horizontal surface is

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On a rough horizontal plane, acceleration of a block of mass .m. is given by `a=P/m - mu_(k) g`……. (i)
Initially, P=F, `a= 5ms^(-2)`
`5=F/10 - mu_(g) (10)`……..(ii) `(therefore m=10 kg)`
When force is doubled i.e., `P = 2F, a = 18 ms^(-2)`
`18 = (2F)/10 - mu_(K)(10)`......(iii)
Multiplying Eq (ii) with 2 and subtracting from Eq. (iii)
`8 = mu_(k) (10) rArr mu_(k) = 8/10 = 0.8`
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