A block of mass M slides along the sides of bowl as shown in the figure. The walls of the bowl are frictionless and the base has coefficient of friction 0.1, and length 0.5m. The block is released from the point A which is 0.2 m high as shown in figure. Then the block comes to rest

Explanation

To solve the problem step by step, we will use the principles of conservation of energy and the work done against friction.

### Step 1: Determine the initial potential energy
The block is released from a height of 0.2 m. The potential energy (PE) at this height can be calculated using the formula:
\[ PE = mgh \]
where:
- \( m \) = mass of the block (we can keep it as \( m \) since it will cancel out later),
- \( g \) = acceleration due to gravity (approximately \( 9.81 \, \text{m/s}^2 \)),
...