A horizontal converyor belt moves with a constant velocity V. A small block is projected with a velocity of 6 mis on it in a direction opposite to the direction of motion of the belt. The block comes to rest relative to the belt in a time 4s. `mu = 0.3 g, g= 10 m//s^(2)`
Find V

Explanation

To solve the problem, let's break it down step by step:

### Step 1: Understand the scenario
A block is projected on a conveyor belt moving with a constant velocity \( V \). The block is initially moving in the opposite direction with a velocity of \( 6 \, \text{m/s} \) and comes to rest relative to the belt in \( 4 \, \text{s} \).

### Step 2: Identify the forces acting on the block
The forces acting on the block include:
- The gravitational force \( mg \) acting downwards.
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