A 2kg block is placed over a 5kg block and both are placed on a smooth horizontal surface. The coefficient of friction between the blocks is 0.10. Find the acceleration of the two blocks if a horizontal force of 14N is applied to the upper block (g = `10ms^(-2)`).

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the forces acting on the upper block (2 kg)
The applied force on the upper block is 14 N. The frictional force acting between the two blocks will oppose the motion. The maximum static friction force can be calculated using the formula:
\[ F_s^{max} = \mu \cdot m_1 \cdot g \]
where:
- \( \mu = 0.10 \) (coefficient of friction)
- \( m_1 = 2 \, \text{kg} \) (mass of the upper block)
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