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If mu,R and S represent coefficient of f...

If `mu,R` and S represent coefficient of friction, normal reaction and distance moved, then the general expression for work against friction

A

`mu` RS

B

`mu + R//S`

C

`mu R//S`

D

`mu S//R`

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To derive the general expression for work done against friction, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Components**: - Let \( \mu \) be the coefficient of friction. - Let \( R \) be the normal reaction force. - Let \( S \) be the distance moved. 2. **Identify the Force of Friction**: - The force of friction \( F \) can be expressed as: \[ F = \mu R \] This equation states that the frictional force is proportional to the normal force and the coefficient of friction. 3. **Calculate Work Done Against Friction**: - Work done \( W \) against friction is given by the formula: \[ W = F \times S \] where \( F \) is the force of friction and \( S \) is the distance moved. 4. **Substitute the Expression for Friction**: - Now, substituting \( F = \mu R \) into the work equation: \[ W = (\mu R) \times S \] 5. **Final Expression**: - Therefore, the general expression for work done against friction becomes: \[ W = \mu R S \] ### Final Answer: The general expression for work done against friction is: \[ W = \mu R S \]
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