Home
Class 12
PHYSICS
An impulse vec(I) changes the velocity o...

An impulse `vec(I)` changes the velocity of a particle from `vec(v)_(1)` to `vec(v)_(2)`. Kinetic energy gained by the particle is :-

A

`I(v_(1)+v_(2))`

B

`I(v_(1) + v_(2))//2`

C

`I(v_(1) -v_(2))`

D

`I(v_(1)-v_(2))//2`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

If a particle is moving as vec(r) = ( vec(i) +2 vec(j))cosomega _(0) t then,motion of the particleis

Two particles of masses m_(1) and m_(2) in projectile motion have velocities vec(v)_(1) and vec(v)_(2) , respectively , at time t = 0 . They collide at time t_(0) . Their velocities become vec(v')_(1) and vec(v')_(2) at time 2 t_(0) while still moving in air. The value of |(m_(1) vec(v')_(1) + m_(2) vec(v')_(2)) - (m_(1) vec(v)_(1) + m_(2) vec(v)_(2))|

If vec(v)_(1)+vec(v)_(2) is perpendicular to vec(v)_(1)-vec(v)_(2) , then

A particle is moving on a circular path such that at any instant its position vector, linear velocity. Angular velocity, angular acceleration with respect to centre are vec(r),vec(v),vec(w),vec(alpha) respectively. Net acceleration of the particle is :-

The position vector of a particle of mass m= 6kg is given as vec(r)=[(3t^(2)-6t) hat(i)+(-4t^(3)) hat(j)] m . Find: (i) The force (vec(F)=mvec(a)) acting on the particle. (ii) The torque (vec(tau)=vec(r)xxvec(F)) with respect to the origin, acting on the particle. (iii) The momentum (vec(p)=mvec(v)) of the particle. (iv) The angular momentum (vec(L)=vec(r)xxvec(p)) of the particle with respect to the origin.

A particle of m=5kg is momentarily at rest at x= at t=. It is acted upon by two forces vec(F)_(1) and vec(F)_(2) . Vec(F)_(1)=70hat(j) N. The direction and manitude of vec(F)_(2) are unknown. The particle experiences a constant acceleration, vec(a) ,in the direction as shown in (figure) Neglect gravity. a.Find the missing force vec(F)_(2) . b. What is the velocity vector of the particle at t=10 s ? c. What third force, vec(F)_(3) is required to make the acceleration of the particle zero? Either give magnitude and direction of vec(F)_(3) or its components.

A particle moves with a tangential acceleration a_(t)=vec(a).hat(v) where vec(a)=(5hat(i)) m//s^(2) . If the speed of the particle is zero at x=0 , then find v (in m//s ) at x=4.9 m .

A charged particle with charge q enters a region of constant, uniform and mututally orthogonal fields vec(E) and vec(B) with a velocity vec(v) perpendicular to both vec(E) and vec(B) , and comes out without any change in magnitude or direction of vec(v) . Then

A particle of specific charge q//m = (pi) C//kg is projected from the origin towards positive x-axis with a velocity of 10 m//s in a uniform magnetic field vec(B) = -2 hat K Tesla. The velocity vec V of the particle after time t =1//6 s will be

A particle of specific charge q//m = (pi) C//kg is projected from the origin towards positive x-axis with a velocity of 10 m//s in a uniform magnetic field vec(B) = -2 hat K Tesla. The velocity vec V of the particle after time t =1//6 s will be