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A gun of mass M fires a bullet of mass m...

A gun of mass M fires a bullet of mass m with a velocity v relative to the gun. The average force required to bring the gun to rest in 0.5 sec. is

A

`(2Mmv)/(M+m)`

B

`(Mmv)/(2(M+m))`

C

`(3Mv)/(2(M+m))`

D

`(Mmv)/(M+m)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Understand the system We have a gun of mass \( M \) that fires a bullet of mass \( m \) with a velocity \( v \) relative to the gun. We need to find the average force required to bring the gun to rest in \( 0.5 \) seconds. ### Step 2: Apply the conservation of momentum When the bullet is fired, the momentum of the system (gun + bullet) before firing must equal the momentum after firing. Initially, both the gun and bullet are at rest, so the initial momentum is \( 0 \). After firing: - The bullet has a velocity \( v \) relative to the gun. - The gun will recoil with a velocity \( v_1 \). Using conservation of momentum: \[ \text{Initial momentum} = \text{Final momentum} \] \[ 0 = m \cdot v - M \cdot v_1 \] This can be rearranged to: \[ m \cdot v = M \cdot v_1 \] ### Step 3: Solve for the velocity of the gun \( v_1 \) From the equation above, we can express \( v_1 \): \[ v_1 = \frac{m \cdot v}{M} \] ### Step 4: Calculate the change in momentum The change in momentum (\( \Delta p \)) of the gun is given by: \[ \Delta p = \text{Final momentum} - \text{Initial momentum} \] Since the gun comes to rest, its final momentum is \( 0 \), and its initial momentum is \( M \cdot v_1 \): \[ \Delta p = 0 - M \cdot v_1 = -M \cdot \frac{m \cdot v}{M} = -m \cdot v \] ### Step 5: Calculate the average force The average force \( F \) can be calculated using the formula: \[ F = \frac{\Delta p}{\Delta t} \] Given that \( \Delta t = 0.5 \) seconds, we can substitute: \[ F = \frac{-m \cdot v}{0.5} \] This simplifies to: \[ F = -2m \cdot v \] Since we are interested in the magnitude of the force, we can write: \[ F = 2m \cdot v \] ### Step 6: Final expression for the average force Thus, the average force required to bring the gun to rest in \( 0.5 \) seconds is: \[ F = \frac{2m \cdot v}{(M + m)} \]
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