Home
Class 12
PHYSICS
When an empty lift is moving down with a...

When an empty lift is moving down with an acceleration of `g/4 ms^(-2)` the tension in the cable is 9000N. When the lift is moving up with an acceleration of `g/3 ms^(-2)` the tension in the cable is

A

16,000 N

B

18,000 N

C

12,000 N

D

15,000 N

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the two scenarios given: when the lift is moving down and when it is moving up. ### Step 1: Analyze the first scenario (Lift moving down) When the lift is moving down with an acceleration of \( \frac{g}{4} \, \text{m/s}^2 \): - Let the mass of the lift be \( m \). - The weight of the lift is \( mg \). - The tension in the cable is \( T \). - According to Newton's second law, we can write the equation of motion: \[ mg - T = m \left(\frac{g}{4}\right) \] ### Step 2: Rearranging the equation Rearranging the equation from Step 1 gives us: \[ T = mg - m \left(\frac{g}{4}\right) \] Factoring out \( m \): \[ T = m \left(g - \frac{g}{4}\right) = m \left(\frac{4g}{4} - \frac{g}{4}\right) = m \left(\frac{3g}{4}\right) \] ### Step 3: Substitute the tension value We know from the problem that \( T = 9000 \, \text{N} \): \[ 9000 = \frac{3mg}{4} \] ### Step 4: Solve for \( mg \) To find \( mg \): \[ 3mg = 9000 \times 4 \] \[ 3mg = 36000 \] \[ mg = \frac{36000}{3} = 12000 \, \text{N} \] ### Step 5: Analyze the second scenario (Lift moving up) Now, when the lift is moving up with an acceleration of \( \frac{g}{3} \, \text{m/s}^2 \): - The equation of motion now becomes: \[ T - mg = m \left(\frac{g}{3}\right) \] ### Step 6: Rearranging the equation for upward motion Rearranging gives: \[ T = mg + m \left(\frac{g}{3}\right) \] Factoring out \( m \): \[ T = m \left(1 + \frac{1}{3}\right)g = m \left(\frac{4g}{3}\right) \] ### Step 7: Substitute \( mg \) value Now substitute \( mg = 12000 \, \text{N} \): \[ T = \frac{4}{3} \times 12000 \] \[ T = 16000 \, \text{N} \] ### Final Answer The tension in the cable when the lift is moving up with an acceleration of \( \frac{g}{3} \, \text{m/s}^2 \) is **16000 N**. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

A lift is moving up with an acceleration of 3.675 m//sec_(2) . The weight of a man-

The mass of a lift if 600kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is :

A boy of mass 40 kg climbs up a rope with an acceleration of 2 ms^(-2) . What is the tension in the rope ?

A balloon with its contents weighing 160 N is moving down with an acceleration of g/2 ms^(-2) . The mass to be removed from it so that the balloon moves up with an acceleration of-g/3 ms^(-2) is

The mass of man when standing on the lift is 60 kg. The weight when the lift is moving upwards with acceration 4.9 ms^(-2) is

A rod is formed by joining two cylinders each having a length l and cross sectional area S. The densities of cylinder are rho and 2rho respectively. The rod is now horizontally suspended in a liquid of density 4 rho with help of two string as shown in the figure. The entire setup is kept inside a lift. For the quantities given in List I select the correct value from those mentioned in List II. {:("List-I",,"List-II"),("(P)Tension in string 1 if the lift is moving upwards with constant velocity",,(1) 11/8 rhoSl g),("(Q)Tension in string 2 if the lift is moving upwards with constant velocity",,(2) 9/8 rhoSlg),("(R)Tension is string 1 if lift is moving downwards with an acceleration of g/2",,(3) 11/4 rhoSlg),("(S)Tension in string 2 if the lift is moving downwards with an acceleration of g/2",,(4) 9/4 rhoSlg):} Choose the correct option :

A pendulum is hanging from the ceiling of a cage. When the cage is moving up with certain acceleration and when it is moving down with the same acceleration, the tensions in the string are T_(1) and T_2 respectively. When the cage moves horizontally with the same acceleration, the tension in the string is,

A man weighing 60 kg is in a lift moving down with an acceleration of 1.8" ms"^(-2) . The force exerted by the floor on him is

A lift of mass 100 kg is moving upwards with an acceleration of 1 m//s^(2) . The tension developed in the string, which is connected to lift is ( g=9.8m//s^(2) )

A balloon of mass m is descending down with an acceleration How much mass should be g/2 removed from it so that it starts moving up with same acceleration?