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Two sounding bodies are producing progre...

Two sounding bodies are producing progressive waves given by `y_1 = 4 sin (400 pi t) `and `y_2 = 3 sin (404 pi t)` , where t is in second which superpose near the ears of a person. The person will hear

A

2 beats per second with intensity ratio `4/3` between maxima and minima

B

2 beats per second with intensity ratio 49 between maxima and minima

C

4 beats per second with intensity ratio 7 between maxima and minima

D

4 beats per second with intensity ratio `4/3` between maxima and minima

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will analyze the two progressive waves given by their equations and determine what the person will hear when these waves superpose. ### Step-by-Step Solution: 1. **Identify the wave equations**: The two waves are given as: \[ y_1 = 4 \sin(400 \pi t) \] \[ y_2 = 3 \sin(404 \pi t) \] 2. **Determine the angular frequencies**: From the wave equations, we can identify the angular frequencies (\(\omega\)): - For \(y_1\): \(\omega_1 = 400 \pi\) - For \(y_2\): \(\omega_2 = 404 \pi\) 3. **Calculate the frequencies**: The relationship between angular frequency and frequency is given by: \[ \omega = 2 \pi f \] Thus, we can find the frequencies: - For \(y_1\): \[ f_1 = \frac{\omega_1}{2\pi} = \frac{400 \pi}{2\pi} = 200 \, \text{Hz} \] - For \(y_2\): \[ f_2 = \frac{\omega_2}{2\pi} = \frac{404 \pi}{2\pi} = 202 \, \text{Hz} \] 4. **Determine the beat frequency**: The beat frequency (\(f_b\)) is given by the difference in frequencies: \[ f_b = |f_2 - f_1| = |202 - 200| = 2 \, \text{Hz} \] This means the person will hear 2 beats per second. 5. **Calculate the intensity ratio**: The intensity of a wave is proportional to the square of its amplitude. The amplitudes are: - \(A_1 = 4\) - \(A_2 = 3\) The maximum intensity (\(I_{max}\)) and minimum intensity (\(I_{min}\)) can be calculated as follows: \[ I_{max} \propto (A_1 + A_2)^2 = (4 + 3)^2 = 7^2 = 49 \] \[ I_{min} \propto (A_1 - A_2)^2 = (4 - 3)^2 = 1^2 = 1 \] Therefore, the intensity ratio is: \[ \frac{I_{max}}{I_{min}} = \frac{49}{1} = 49 \] ### Conclusion: The person will hear 2 beats per second, and the intensity ratio of the maximum to minimum intensity is 49:1.
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