An observer measures speed of light to be C, when he is stationary with respect to the source. If the observer moves with velocity V towards the source then the velocity of light observed will be

Options

A. C - V
B. C + V
C. `sqrt(1 -V^2/C^2)`
D. C

Answer

To solve the problem, we need to understand the behavior of light speed in different reference frames according to the principles of physics, particularly Einstein's theory of relativity.

### Step-by-Step Solution:

1. **Understanding the Speed of Light**: The speed of light in a vacuum is a universal constant denoted by \( C \). This means that it does not change regardless of the motion of the observer or the source.

2. **Observer at Rest**: When the observer is stationary with respect to the source of light, they measure the speed of light to be \( C \).

3. **Observer in Motion**: If the observer starts moving towards the source of light with a velocity \( V \), we need to analyze how this affects the measurement of light speed.

4. **Relativity Principle**: According to the principles of relativity, the speed of light remains constant at \( C \) for all observers, regardless of their motion relative to the source of light.

5. **Conclusion**: Therefore, even if the observer moves towards the source with velocity \( V \), the speed of light that they measure will still be \( C \).

### Final Answer:
The velocity of light observed will be \( C \).

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