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The time lag between two particles vibra...

The time lag between two particles vibrating in a progressive wave seperated by a distance 20m is 0.02s. The wave velocity if the frequency of the wave is 500Hz, is

A

`1000ms^(-1)`

B

`500ms^(-1)`

C

`2000ms^(-1)`

D

`250 ms^(-1)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the wave velocity given the distance between two particles and the time lag between their vibrations. Here’s the step-by-step solution: ### Step 1: Identify the given values - Distance (s) = 20 meters - Time lag (t) = 0.02 seconds - Frequency (f) = 500 Hz (though we won't need this value for calculating wave velocity directly) ### Step 2: Use the formula for wave velocity The wave velocity (v) can be calculated using the formula: \[ v = \frac{s}{t} \] where: - \( v \) is the wave velocity, - \( s \) is the distance between the two particles, - \( t \) is the time lag. ### Step 3: Substitute the values into the formula Now, we substitute the given values into the formula: \[ v = \frac{20 \, \text{m}}{0.02 \, \text{s}} \] ### Step 4: Perform the calculation Calculating the above expression: \[ v = \frac{20}{0.02} = 1000 \, \text{m/s} \] ### Step 5: State the final answer Thus, the wave velocity is: \[ v = 1000 \, \text{m/s} \]
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