Home
Class 12
PHYSICS
At room temperature, a dilute solution o...

At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be `1.74 xx 10^(-x)` mm Hg. The numerical value of x is _____________. (Molar mass of urea = 60 g `mol^(-1)`).

A

10

B

`sqrt10`

C

`10^(-6)`

D

`10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • WAVE MOTION

    AAKASH SERIES|Exercise PRACTICE SET (EXERCISE-II (LEVEL-II(ADVANCED) MATRIX MATCHING TYPE QUESTIONS))|1 Videos

  • WAVE MOTION

    AAKASH SERIES|Exercise PRACTICE SET (EXERCISE-V (LEVEL-I(MAIN) STRAIGHT OBJECTIVE TYPE QUESTIONS))|15 Videos

  • WAVE MOTION

    AAKASH SERIES|Exercise PRACTICE SET (EXERCISE-III (LEVEL-II(ADVANCED) INTEGER TYPE QUESTIONS))|2 Videos

  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise EXERCISE -3|66 Videos

  • WAVE MOTION AND SOUND

    AAKASH SERIES|Exercise PROBLEMS (LEVEL - II)|97 Videos

Similar Questions

Explore conceptually related problems

At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea =60 g "mol"^(-1) )

An aqueous solution of glucose was prepared by dissolving 18g of glucose in 90g of water. The relative lowering in vapour pressure is

A solution of sucrose (molar mass =342) is prepared by dissolving 688.4 g in 1000 g of water. Calculate The vapour pressure of solution at 293 K.

An aqueous solution is made by dissolving 10g of glucose (C_(6)H_(12)O_(6)) in 90g of water at 300K. If the vapour pressure of pure water at 300 K is 32.8 mm Hg, what would be the vapour pressure of the solution?

What mass of urea be dissolved in 171 g of water so as to decrease the vapour pressure of water by 5% ?

What weight of solute (mol. Wt. 60) is required to dissolve in 180 g of water to reduce the vapour pressure to 4//5^(th) of pure water ?

What weight of solute (mol. Wt. 60) is required to dissolve in 180 g of water to reduce the vapour pressure to 4//5^(th) of pure water ?

A solution is prepared by dissolving 10g of non-volatile solute in 200g of water. It has a vapour pressure of 31.84 mm Hg at 308 K. Calculate the molar mass of the solute. (Vapour pressure of pure water at 308K =32 mm Hg)

Vapour pressure of pure water at 298 k is 23.8 mm Hg. Calculate the lowering of vapour pressure caused by adding 5g of sucrose in 50 g of water.

6.0 g of urea (molecular mass = 60) was dissolved in 9.9 moles of water. If the vapour pressure of pure water is P^(@) , the vapour pressure of solution is :