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The frequency of a source of sound as me...

The frequency of a source of sound as measured by an observer when the source is moving towards him with a speed of 30 m/s is 720 Hz. The apparent frequency when the source is moving away after crossing the observer is `x xx 10^2 Hz` what is the value of x. ......... (velocity of sound is 330 m/s)

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To solve the problem step by step, we will use the Doppler effect formula for sound. ### Step 1: Identify the known values - Speed of sound, \( v = 330 \, \text{m/s} \) - Speed of the source, \( v_s = 30 \, \text{m/s} \) - Apparent frequency when the source is moving towards the observer, \( f_1 = 720 \, \text{Hz} \) ### Step 2: Use the Doppler effect formula for the source moving towards the observer The formula for the apparent frequency when the source is moving towards the observer is given by: \[ f_1 = \frac{v}{v - v_s} f_0 \] Where \( f_0 \) is the actual frequency of the source. ### Step 3: Substitute the known values into the formula Substituting the known values into the formula: \[ 720 = \frac{330}{330 - 30} f_0 \] This simplifies to: \[ 720 = \frac{330}{300} f_0 \] ### Step 4: Solve for the actual frequency \( f_0 \) Rearranging the equation to find \( f_0 \): \[ f_0 = 720 \times \frac{300}{330} \] Calculating \( f_0 \): \[ f_0 = 720 \times \frac{300}{330} = 720 \times \frac{10}{11} = 7200 / 11 \approx 654.55 \, \text{Hz} \] ### Step 5: Use the Doppler effect formula for the source moving away from the observer Now, when the source is moving away from the observer, the formula for the apparent frequency is: \[ f_2 = \frac{v}{v + v_s} f_0 \] We need to find \( f_2 \) which is given as \( x \times 10^2 \, \text{Hz} \). ### Step 6: Substitute \( f_0 \) into the formula for \( f_2 \) Substituting the values into the formula: \[ f_2 = \frac{330}{330 + 30} f_0 = \frac{330}{360} f_0 \] Substituting \( f_0 \): \[ f_2 = \frac{330}{360} \times \frac{7200}{11} \] ### Step 7: Calculate \( f_2 \) Calculating \( f_2 \): \[ f_2 = \frac{330 \times 7200}{360 \times 11} = \frac{2376000}{3960} \approx 600 \, \text{Hz} \] ### Step 8: Express \( f_2 \) in terms of \( x \) Since \( f_2 = x \times 10^2 \): \[ 600 = x \times 10^2 \] Thus, solving for \( x \): \[ x = \frac{600}{100} = 6 \] ### Final Answer The value of \( x \) is \( 6 \).
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