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The speed of a wave on a string is 150 m...

The speed of a wave on a string is 150 m/s when the tension is 120 N . The percentage increase in the tension in order to raise the wave speed by 20% is

A

0.44

B

0.4

C

0.2

D

0.1

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the outlined process to find the percentage increase in tension required to raise the wave speed by 20%. ### Step 1: Determine the new speed (V2) The initial speed (V1) of the wave is given as 150 m/s. We need to increase this speed by 20%. \[ \text{New Speed (V2)} = V1 + 20\% \text{ of } V1 \] Calculating 20% of V1: \[ 20\% \text{ of } 150 = \frac{20}{100} \times 150 = 30 \] Thus, the new speed V2 is: \[ V2 = 150 + 30 = 180 \text{ m/s} \] ### Step 2: Relate the speeds and tensions The relationship between the speed of a wave on a string and the tension is given by: \[ \frac{V2}{V1} = \sqrt{\frac{T2}{T1}} \] Where: - \( V1 = 150 \, \text{m/s} \) - \( V2 = 180 \, \text{m/s} \) - \( T1 = 120 \, \text{N} \) - \( T2 \) is the new tension we need to find. ### Step 3: Square both sides Squaring both sides of the equation gives: \[ \left(\frac{V2}{V1}\right)^2 = \frac{T2}{T1} \] Substituting the known values: \[ \left(\frac{180}{150}\right)^2 = \frac{T2}{120} \] ### Step 4: Calculate the left side Calculating \( \frac{180}{150} \): \[ \frac{180}{150} = 1.2 \] Now squaring it: \[ (1.2)^2 = 1.44 \] ### Step 5: Solve for T2 Now substituting back into the equation: \[ 1.44 = \frac{T2}{120} \] Multiplying both sides by 120 gives: \[ T2 = 1.44 \times 120 = 172.8 \, \text{N} \] ### Step 6: Calculate the percentage increase in tension To find the percentage increase in tension, we use the formula: \[ \text{Percentage Increase} = \frac{T2 - T1}{T1} \times 100\% \] Substituting the values: \[ \text{Percentage Increase} = \frac{172.8 - 120}{120} \times 100\% \] Calculating the difference: \[ 172.8 - 120 = 52.8 \] Now substituting this back into the percentage formula: \[ \text{Percentage Increase} = \frac{52.8}{120} \times 100\% = 44\% \] ### Final Answer The percentage increase in tension required to raise the wave speed by 20% is **44%**. ---
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