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A person with vibrating tuning fork of f...

A person with vibrating tuning fork of frequency 338 Hz is moving towards a vertical wall with speed of `2 ms^(-1)` Velocity of sound in air is `340 ms^(-1)` The number of beats heard per second is

A

2

B

4

C

6

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will follow these steps: ### Step 1: Identify the given values - Frequency of the tuning fork (f) = 338 Hz - Speed of the person (vs) = 2 m/s - Velocity of sound in air (v) = 340 m/s ### Step 2: Calculate the apparent frequency (f') heard by the wall When the source of sound (the person with the tuning fork) is moving towards a stationary observer (the wall), the apparent frequency can be calculated using the formula: \[ f' = \frac{v}{v - v_s} \cdot f \] Substituting the values: \[ f' = \frac{340}{340 - 2} \cdot 338 \] \[ f' = \frac{340}{338} \cdot 338 \] \[ f' = 340 \text{ Hz} \] So, the frequency heard by the wall is 340 Hz. ### Step 3: Calculate the apparent frequency (f'') heard by the person after reflection Now, the wall acts as a source of sound, and the person is moving towards it. The new apparent frequency can be calculated using: \[ f'' = \frac{v + v_o}{v - v_s} \cdot f' \] Here, \(v_o\) (the velocity of the observer, which is the person) is also 2 m/s. Substituting the values: \[ f'' = \frac{340 + 2}{340 - 0} \cdot 340 \] \[ f'' = \frac{342}{340} \cdot 340 \] \[ f'' = 342 \text{ Hz} \] ### Step 4: Calculate the beat frequency The beat frequency is the difference between the two frequencies: \[ \text{Beat frequency} = f'' - f' \] Substituting the values: \[ \text{Beat frequency} = 342 - 340 = 2 \text{ Hz} \] ### Step 5: Conclusion The number of beats heard per second is 2 Hz. ---
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