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The refractive indices of glycerine and ...

The refractive indices of glycerine and diamond with respect to air are 1.4 and 2.4 respectively. Calculate the speed of light in glycerine and diamond. From these results, calculate the refractive index of diamong with respect to glycerine. `(c=3xx10^(8)m//s)`

A

`2.143xx10^(8)m//s, 1.250xx10^(8)m//s, 1.714`

B

`1.143xx10^(8)m//s,1.250xx10^(8)m//s, 1.714`

C

`2.143xx10^(8)m//s,2.250xx10^(8)m//s, 1.714`

D

`2.143xx10^(8)m//s,1.250xx10^(8)m//s,1.514`

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The correct Answer is:
To solve the problem, we need to calculate the speed of light in glycerine and diamond, and then find the refractive index of diamond with respect to glycerine. ### Step 1: Calculate the speed of light in glycerine The formula to calculate the speed of light in a medium is given by: \[ V = \frac{C}{n} \] where: - \( V \) is the speed of light in the medium, - \( C \) is the speed of light in vacuum (or air), which is \( 3 \times 10^8 \, \text{m/s} \), - \( n \) is the refractive index of the medium. For glycerine, the refractive index \( n_g \) is given as 1.4. Therefore, we can calculate the speed of light in glycerine (\( V_g \)): \[ V_g = \frac{C}{n_g} = \frac{3 \times 10^8}{1.4} \] Calculating this gives: \[ V_g = \frac{3 \times 10^8}{1.4} \approx 2.14 \times 10^8 \, \text{m/s} \] ### Step 2: Calculate the speed of light in diamond Now, we will calculate the speed of light in diamond. The refractive index \( n_d \) for diamond is given as 2.4. Thus, we can calculate the speed of light in diamond (\( V_d \)): \[ V_d = \frac{C}{n_d} = \frac{3 \times 10^8}{2.4} \] Calculating this gives: \[ V_d = \frac{3 \times 10^8}{2.4} \approx 1.25 \times 10^8 \, \text{m/s} \] ### Step 3: Calculate the refractive index of diamond with respect to glycerine The refractive index of diamond with respect to glycerine (\( n_{dg} \)) can be calculated using the formula: \[ n_{dg} = \frac{n_d}{n_g} \] Substituting the values we have: \[ n_{dg} = \frac{2.4}{1.4} \] Calculating this gives: \[ n_{dg} \approx 1.714 \] ### Summary of Results - Speed of light in glycerine: \( V_g \approx 2.14 \times 10^8 \, \text{m/s} \) - Speed of light in diamond: \( V_d \approx 1.25 \times 10^8 \, \text{m/s} \) - Refractive index of diamond with respect to glycerine: \( n_{dg} \approx 1.714 \)
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AAKASH SERIES-GEOMETRICAL OPTICS-LECTURE SHEET (EXERCISE II LEVEL -I (MAIN) STRAIGHT OBJECTIVE TYPE QUESTIONS)
  1. Absolute refractive index of a medium is X. Refractive index of same m...

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  2. The refractive indices of glycerine and diamond with respect to air ar...

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  3. A monochromatic light passes through a glass slab (mu = (3)/(2)) of th...

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  4. A glass slab of thickness 8 cms contains the same number of waves as 1...

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  5. The optical path of a monochromatic light is the same if it goes throu...

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  6. A ray of light incidents on a refracting surface at 30^(@) with the su...

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  7. A unit vector along the incident ray of light is hat(i). The unit vect...

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  8. The velocities of light in two different media are 2*10^8m/s and 2.5 *...

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  9. Light takes t(1) second to travel a distance x cm in vacuum and the sa...

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  10. A ray of light from a denser medium strikes a rare medium as shown in ...

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  11. The refractive index of the core of an optical fibre is mu(2) and that...

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  12. The refractive index of a prism for a monochromatic wave is sqrt(2)and...

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  13. A trianglular prims of glass is shown in the figure. A ray incident no...

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  14. Under minimum deviation condition in a prism, if a ray is incident at ...

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  15. A ray of light passes through an equilateral glass prism will be such ...

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  16. The refractive indices of violet and red light are 1.54 and 1.52 respe...

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  17. The refractive indices of crown glass prism of C,D and F lines are 1.5...

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