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A mark on the surface of a glass spehre ...

A mark on the surface of a glass spehre `(mu=1.5)` is viewed from a diametrically opposite position. It appears to be at a distance 10 cm from its actual position. The radius of the sphere is

A

5 cm

B

10 cm

C

15 cm

D

25 cm

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step-by-step, we will use the concepts of geometrical optics, particularly the refraction at a spherical surface. ### Step-by-Step Solution: 1. **Understanding the Problem**: - We have a glass sphere with a refractive index \( \mu_1 = 1.5 \). - The mark on the surface of the sphere is viewed from the diametrically opposite position. - It appears to be at a distance of 10 cm from its actual position. 2. **Setting Up the Coordinates**: - Let the radius of the sphere be \( r \). - The object (mark) is located on the surface of the sphere, so its actual position can be considered as \( u = -2r \) (negative because it is on the same side as the incoming light). - The image distance \( v \) is what we need to find. 3. **Applying the Refraction Formula**: - The formula for refraction at a spherical surface is given by: \[ \frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R} \] - Here, \( \mu_2 = 1 \) (for air), \( \mu_1 = 1.5 \), and \( R = -r \) (the radius is negative for a convex surface). 4. **Substituting Values**: - Substitute the values into the formula: \[ \frac{1}{v} - \frac{1.5}{-2r} = \frac{1 - 1.5}{-r} \] - This simplifies to: \[ \frac{1}{v} + \frac{1.5}{2r} = \frac{-0.5}{-r} \] - Further simplifying gives: \[ \frac{1}{v} + \frac{0.75}{r} = \frac{0.5}{r} \] 5. **Finding \( \frac{1}{v} \)**: - Rearranging the equation: \[ \frac{1}{v} = \frac{0.5}{r} - \frac{0.75}{r} = \frac{-0.25}{r} \] - Thus, we find: \[ v = -\frac{4r}{1} \] 6. **Relating \( v \) to the Given Information**: - The image appears to be at a distance of 10 cm from its actual position, which means: \[ |v| = 2r + 10 \] - Substituting \( v = -4r \): \[ 4r = 2r + 10 \] 7. **Solving for \( r \)**: - Rearranging gives: \[ 4r - 2r = 10 \implies 2r = 10 \implies r = 5 \text{ cm} \] 8. **Conclusion**: - The radius of the sphere is \( r = 5 \) cm. ### Final Answer: The radius of the sphere is **5 cm**.
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