Home
Class 12
PHYSICS
The first factor length f(1) for refract...

The first factor length `f_(1)` for refraction at a spherical surface is defined as the value of u corresponding to `v=oo` (as shown) with refractive indices of two mediums, as `n_(1)` and `n_(2)`. The second focal length `f_(2)` is defined as value of v for `u=oo`.

A

`f_(2)` is equal to `(n_(2)R)/((n_(2)-n_(1)))`

B

`f_(1)` is equal to `(n_(2)R)/((n_(2)-n_(1)))`

C

`f_(2)` is equal to `(-)(n_(1)R)/((n_(2)-n_(1)))`

D

`f_(1)` is equal to `(n_(1)R)/((n_(2)-n_(1)))`

Text Solution

Verified by Experts

The correct Answer is:
C, D
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL OPTICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE -I (LEVEL-II LECTURE SHEET (ADVANCED) LINKED COMPREHENSION TYPE QUESTIONS)|8 Videos
  • GEOMETRICAL OPTICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE -I (LEVEL-II LECTURE SHEET (ADVANCED) MATRIX MATCHING TYPE QUESTIONS)|1 Videos
  • GEOMETRICAL OPTICS

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE -I (LEVEL-II LECTURE SHEET (ADVANCED) STRAIGHT OBJECTIVE TYPE QUESTIONS)|29 Videos
  • ELEMENTS OF VECTORS

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|10 Videos
  • LAWS OF MOTION

    AAKASH SERIES|Exercise PRACTICE EXERCISE|106 Videos

Similar Questions

Explore conceptually related problems

Two thin lenses of focal lengths f_(1) and f_(2) are in contact. The focal length of this combination is

Obtain an expression for refraction at a single convex spherical surface separating the two media having refractive indices mu_(1) (rarer medium) and mu_(2) (denser medium) i.e., a relation between u, v, mu_(1),mu_(2) and R.

A lens made of material of Refractive index mu_(2) is surrounded by a medium of Refractive Index mu_(1) . The focal length f is related as

A lens made of material of Refractive index mu_(2) is surrounded by a medium of Refractive Index mu_(1) . The focal length f is related as

Two refracting media are separated by a spherical interfaces as shown in the figure. AB is the principal axis, mu_1 and mu_2 are the refractive indices of medium of incidence and medium of refraction respectively. Then,

The refractive index of a lens material is 1.5 and focal length f. Due to some chemical changes in the material, its refractive index has increased by 2%. The percentage change in its focal length is

Assertion : The radius of curvature of a mirror is double of the focal length. Reason : A concave mirror of focal length f in air is used in a medium of refractive index 2. Then the focal length of mirror in medium becomes 2f.

If u_1 and u_2 are the units selected in two systems of measurement and n_1 and n_2 their numerical values, then

µ_(1) and µ_(2) are the refractive index of two mediums and v_(1) and v_(2) are the velocity of light in these in two mediums respectively. Then, the relation connecting these quantities is

Image distance |v| vs object distance |u| curve for two biconvex lenses with same radii of curvatures is shown in the figure. If refractive index of lens 1 is 5/2 , then refractive index of lens 2 is.