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In a binomial distribution n=400, p=1//5...

In a binomial distribution n=400, `p=1//5`, It's standard deviation is

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To find the standard deviation of a binomial distribution with parameters \( n = 400 \) and \( p = \frac{1}{5} \), we can follow these steps: ### Step 1: Understand the formula for standard deviation in a binomial distribution. The standard deviation \( \sigma \) of a binomial distribution is given by the formula: \[ \sigma = \sqrt{n \cdot p \cdot (1 - p)} \] where \( n \) is the number of trials, \( p \) is the probability of success, and \( (1 - p) \) is the probability of failure. ### Step 2: Substitute the values into the formula. Given: - \( n = 400 \) - \( p = \frac{1}{5} \) We can substitute these values into the formula: \[ \sigma = \sqrt{400 \cdot \frac{1}{5} \cdot (1 - \frac{1}{5})} \] ### Step 3: Calculate \( 1 - p \). First, calculate \( 1 - p \): \[ 1 - p = 1 - \frac{1}{5} = \frac{4}{5} \] ### Step 4: Substitute \( 1 - p \) back into the formula. Now substitute \( 1 - p \) into the formula: \[ \sigma = \sqrt{400 \cdot \frac{1}{5} \cdot \frac{4}{5}} \] ### Step 5: Simplify the expression inside the square root. Now, simplify the expression: \[ \sigma = \sqrt{400 \cdot \frac{1 \cdot 4}{5 \cdot 5}} = \sqrt{400 \cdot \frac{4}{25}} \] \[ = \sqrt{\frac{1600}{25}} = \sqrt{64} = 8 \] ### Step 6: State the final answer. Thus, the standard deviation \( \sigma \) is: \[ \sigma = 8 \] ### Final Answer: The standard deviation of the binomial distribution is **8**. ---
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