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A random variable has the following dist...

A random variable has the following distribution.
`{:(x=x_(i),,-3,,-2,,-1,,0,,1,,2),(P(x=x_(i)),,0.1,,2K,,3K,,7K,,0.2,,0.1):}`
Then for the values, A = K, B = Mean, C = Variance, the ascending order is

A

a) A, B, C

B

b) B, A, C

C

c) C, B, A

D

d) C, A, B

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the values of \( K \), the mean \( B \), and the variance \( C \) of the given random variable distribution. The ascending order of these values will be determined at the end. ### Step 1: Finding \( K \) We know that the sum of all probabilities must equal 1. The given probabilities are: - \( P(X = -3) = 0.1 \) - \( P(X = -2) = 2K \) - \( P(X = -1) = 3K \) - \( P(X = 0) = 7K \) - \( P(X = 1) = 0.2 \) - \( P(X = 2) = 0.1 \) Setting up the equation: \[ 0.1 + 2K + 3K + 7K + 0.2 + 0.1 = 1 \] Combining like terms: \[ 0.4 + 12K = 1 \] Solving for \( K \): \[ 12K = 1 - 0.4 \] \[ 12K = 0.6 \] \[ K = \frac{0.6}{12} = 0.05 \] Thus, \( A = K = 0.05 \). ### Step 2: Finding the Mean \( B \) The mean \( B \) (or \( \mu \)) is calculated using the formula: \[ \mu = \sum (x_i \cdot P(x_i)) \] Calculating each term: \[ \mu = (-3 \cdot 0.1) + (-2 \cdot 2K) + (-1 \cdot 3K) + (0 \cdot 7K) + (1 \cdot 0.2) + (2 \cdot 0.1) \] Substituting \( K = 0.05 \): \[ \mu = (-3 \cdot 0.1) + (-2 \cdot 0.1) + (-1 \cdot 0.15) + (0) + (0.2) + (0.2) \] Calculating each term: \[ \mu = -0.3 - 0.1 - 0.15 + 0 + 0.2 + 0.2 \] \[ \mu = -0.3 - 0.1 - 0.15 + 0.4 \] \[ \mu = -0.25 \] Thus, \( B = \mu = -0.25 \). ### Step 3: Finding the Variance \( C \) The variance \( C \) is calculated using the formula: \[ C = \sum (x_i^2 \cdot P(x_i)) - \mu^2 \] Calculating \( \sum (x_i^2 \cdot P(x_i)) \): \[ C = [(-3)^2 \cdot 0.1] + [(-2)^2 \cdot 2K] + [(-1)^2 \cdot 3K] + [0^2 \cdot 7K] + [1^2 \cdot 0.2] + [2^2 \cdot 0.1] \] Substituting \( K = 0.05 \): \[ C = [9 \cdot 0.1] + [4 \cdot 0.1] + [1 \cdot 0.15] + [0] + [0.2] + [4 \cdot 0.1] \] Calculating each term: \[ C = 0.9 + 0.4 + 0.15 + 0 + 0.2 + 0.4 \] \[ C = 0.9 + 0.4 + 0.15 + 0.2 + 0.4 = 2.05 \] Now, we need to subtract \( \mu^2 \): \[ \mu^2 = (-0.25)^2 = 0.0625 \] Thus, \[ C = 2.05 - 0.0625 = 1.9875 \] ### Step 4: Ascending Order of \( A, B, C \) We have: - \( A = K = 0.05 \) - \( B = \mu = -0.25 \) - \( C = 1.9875 \) Now, arranging these values in ascending order: \[ B < A < C \quad \text{or} \quad -0.25 < 0.05 < 1.9875 \] ### Final Result The ascending order is: \[ B, A, C \]
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