Home
Class 12
MATHS
Assertion (A): The roots of the equation...

Assertion (A): The roots of the equation `a(b-c)x^(2)+b(c-a)x+c(a-b)=0` are 1, `(c(a-b))/(a(b-c))`
Reason (R): If a+b+c=0 then the roots of `ax^(2)+bx+c=0` are 1, `(c)/(a)`

A

Both A, R are true and R explain Assertion

B

Both A, R are true but R does't explain A

C

A is true R is false

D

A is false R is true

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem, we need to analyze both the assertion (A) and the reason (R) provided in the question. ### Step 1: Analyze the Reason (R) The reason states that if \( a + b + c = 0 \), then the roots of the equation \( ax^2 + bx + c = 0 \) are \( 1 \) and \( \frac{c}{a} \). 1. **Substituting \( x = 1 \)**: - We substitute \( x = 1 \) into the equation \( ax^2 + bx + c \): \[ a(1)^2 + b(1) + c = a + b + c \] - Since \( a + b + c = 0 \), we conclude that \( x = 1 \) is indeed a root. 2. **Using the Product of Roots**: - The product of the roots of the quadratic equation \( ax^2 + bx + c = 0 \) is given by \( \frac{c}{a} \). - If one root is \( 1 \), we can express the product of the roots as: \[ 1 \cdot r = \frac{c}{a} \] where \( r \) is the other root. Thus, \( r = \frac{c}{a} \). ### Conclusion for Reason (R): Since both parts of the reason are verified, we conclude that the reason (R) is true. ### Step 2: Analyze the Assertion (A) The assertion states that the roots of the equation \( a(b-c)x^2 + b(c-a)x + c(a-b) = 0 \) are \( 1 \) and \( \frac{c(a-b)}{a(b-c)} \). 1. **Sum of Coefficients**: - We find the sum of the coefficients of the equation: \[ a(b-c) + b(c-a) + c(a-b) \] - Simplifying this: \[ ab - ac + bc - ab + ca - bc = 0 \] - Since the sum of the coefficients is \( 0 \), \( x = 1 \) is a root of the equation. 2. **Product of Roots**: - The product of the roots for the quadratic equation \( a(b-c)x^2 + b(c-a)x + c(a-b) = 0 \) is given by: \[ \frac{c(a-b)}{a(b-c)} \] - Since we already established that one root is \( 1 \), we can express the product of the roots as: \[ 1 \cdot r = \frac{c(a-b)}{a(b-c)} \] - Therefore, the second root \( r \) is indeed \( \frac{c(a-b)}{a(b-c)} \). ### Conclusion for Assertion (A): Since both parts of the assertion are verified, we conclude that the assertion (A) is true. ### Final Conclusion: Both the assertion (A) and reason (R) are true, and the reason explains the assertion. Therefore, the final answer is that both statements are true. ---
Promotional Banner

Similar Questions

Explore conceptually related problems

The roots of the equation (b-c) x^2 +(c-a)x+(a-b)=0 are

The roots of the equation a(b-2c)x^(2)+b(c-2a)x+c(a-2b)=0 are, when ab+bc+ca=0

If the roots of the equation a(b-c)x^2+b(c-a)x+c(a-b)=0 are equal, show that 2//b=1//a+1// c dot

If the roots of the equation a(b-c)x^2+b(c-a)x+c(a-b)=0 are equal, show that 2//b=1//a+1//cdot

If the roots of the equation (b-c)x^2+(c-a)x+(a-b)=0 are equal, then prove that 2b=a+c .

If the roots of the equation (b-c)x^2+(c-a)x+(a-b)=0 are equal, then prove that 2b=a+c

If the roots of the equation (b-c)x^2+(c-a)x+(a-b)=0 are equal then a,b,c will be in

If the roots of equation a(b-c)x^2+b(c-a)x+c(a-b)=0 be equal prove that a,b,c are in H.P.

The roots of the quadratic equation (a + b-2c)x^2+ (2a-b-c) x + (a-2b + c) = 0 are

If a lt c lt b then the roots of the equation (a−b)x^2 +2(a+b−2c)x+1=0 are