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The equation whose roots are half of roo...

The equation whose roots are half of roots of the equation `2x^(2) + 5x + 4= 0` is

A

`8x^(2)+10x+1=0`

B

`4x^(2)+5x+2=0`

C

`8x^(2)+5x+1=0`

D

`16x^(2)+5x+1=0`

Text Solution

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The correct Answer is:
To find the equation whose roots are half of the roots of the given quadratic equation \(2x^2 + 5x + 4 = 0\), we can follow these steps: ### Step 1: Identify the roots of the given equation The given quadratic equation is: \[ 2x^2 + 5x + 4 = 0 \] Let the roots of this equation be \(\alpha\) and \(\beta\). ### Step 2: Calculate the sum and product of the roots Using Vieta's formulas: - The sum of the roots \((\alpha + \beta)\) is given by: \[ \alpha + \beta = -\frac{\text{coefficient of } x}{\text{coefficient of } x^2} = -\frac{5}{2} \] - The product of the roots \((\alpha \beta)\) is given by: \[ \alpha \beta = \frac{\text{constant term}}{\text{coefficient of } x^2} = \frac{4}{2} = 2 \] ### Step 3: Determine the new roots We need to find the equation whose roots are half of the original roots. Therefore, the new roots \(\alpha'\) and \(\beta'\) are: \[ \alpha' = \frac{\alpha}{2}, \quad \beta' = \frac{\beta}{2} \] ### Step 4: Calculate the sum and product of the new roots - The sum of the new roots \((\alpha' + \beta')\) is: \[ \alpha' + \beta' = \frac{\alpha}{2} + \frac{\beta}{2} = \frac{\alpha + \beta}{2} = \frac{-\frac{5}{2}}{2} = -\frac{5}{4} \] - The product of the new roots \((\alpha' \beta')\) is: \[ \alpha' \beta' = \frac{\alpha}{2} \cdot \frac{\beta}{2} = \frac{\alpha \beta}{4} = \frac{2}{4} = \frac{1}{2} \] ### Step 5: Form the new quadratic equation Using the sum and product of the new roots, we can form the quadratic equation: \[ x^2 - (\alpha' + \beta')x + \alpha' \beta' = 0 \] Substituting the values we found: \[ x^2 - \left(-\frac{5}{4}\right)x + \frac{1}{2} = 0 \] This simplifies to: \[ x^2 + \frac{5}{4}x + \frac{1}{2} = 0 \] ### Step 6: Eliminate fractions by multiplying through by 4 To eliminate the fractions, we multiply the entire equation by 4: \[ 4x^2 + 5x + 2 = 0 \] ### Conclusion The required quadratic equation whose roots are half of the roots of the original equation is: \[ \boxed{4x^2 + 5x + 2 = 0} \]
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