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If alpha, beta are roots of ax^(2) + bx...

If `alpha, beta ` are roots of `ax^(2) + bx +c =0,` then the equatin whose roots are `2+ alpha, 2 +beta,` is

A

`ax^(2) + (4a - b)x + 4a - 2b + c = 0`

B

`ax^(2) + (4a - b)x + 4a + 2b + c = 0`

C

`ax^(2) + (b-4a)x + 4a +2b + c = 0`

D

`ax^(2) + (b-4a)x + 4a -2b + c = 0`

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The correct Answer is:
D
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