Select the wrong statement with respect to glycolysis

Options

A. It occurs outside mitochondira
B. It is an anaerobic phase
C. Glucose undergoes partial oxidation to form 2 molecules of pyruvic acid
D. Glucose is phosphorylated to glucose-6-phosphate by isomerase enzyme

Answer

### Step-by-Step Solution:

1. **Understanding Glycolysis**: Glycolysis is a metabolic process that breaks down glucose into pyruvic acid, producing energy in the form of ATP. It occurs in the cytoplasm of the cell.

2. **Identifying the Statements**: The question asks to select the wrong statement regarding glycolysis. We need to analyze each statement provided.

3. **Evaluating Each Statement**:
- **Statement 1**: "It occurs outside mitochondria."
- This is true. Glycolysis takes place in the cytoplasm, which is outside the mitochondria.
- **Statement 2**: "It is an anaerobic phase."
- This is also true. Glycolysis does not require oxygen, making it an anaerobic process.
- **Statement 3**: "Glucose undergoes partial oxidation."
- This statement is correct as glucose is partially oxidized to form pyruvic acid.
- **Statement 4**: "Glucose is phosphorylated to glucose-6-phosphate by isomerase enzyme."
- This statement is incorrect. The phosphorylation of glucose to glucose-6-phosphate is catalyzed by the enzyme hexokinase, not isomerase.

4. **Conclusion**: The wrong statement regarding glycolysis is: "Glucose is phosphorylated to glucose-6-phosphate by isomerase enzyme."