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A parallelogram is cut by two set of n p...

A parallelogram is cut by two set of n parallel lines, parallel to the sides of the parallelo-gram. The number of parallelograms formed is

A

`(""^(n +2)C_(2))(""^(n+2)C_(2))`

B

`(""^(n)C_(2))(""^(n+1)C_(2))`

C

`(""^(n)C_(2))(""^(n+2)C_(2))`

D

`(""^(n)C_(2))(""^(n)C_(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of parallelograms formed when a parallelogram is cut by two sets of \( n \) parallel lines (each set parallel to one of the sides of the parallelogram), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a parallelogram with two sets of \( n \) parallel lines. - One set of \( n \) lines is parallel to one pair of opposite sides of the parallelogram. - The other set of \( n \) lines is parallel to the other pair of opposite sides. 2. **Counting Total Lines**: - The original sides of the parallelogram contribute 2 lines (one for each side). - Thus, the total number of lines parallel to one set of sides becomes \( n + 2 \) (the \( n \) lines plus the 2 original sides). - Similarly, for the other set of sides, we also have \( n + 2 \) lines. 3. **Choosing Lines to Form Parallelograms**: - To form a parallelogram, we need to select 2 lines from the first set (which has \( n + 2 \) lines) and 2 lines from the second set (which also has \( n + 2 \) lines). - The number of ways to choose 2 lines from \( n + 2 \) lines is given by the combination formula \( \binom{n + 2}{2} \). 4. **Calculating the Total Number of Parallelograms**: - Therefore, the total number of parallelograms formed is the product of the combinations from both sets: \[ \text{Total Parallelograms} = \binom{n + 2}{2} \times \binom{n + 2}{2} \] 5. **Final Expression**: - This can be simplified to: \[ \text{Total Parallelograms} = \left( \binom{n + 2}{2} \right)^2 \] ### Conclusion: The number of parallelograms formed is \( \binom{n + 2}{2} \times \binom{n + 2}{2} \).
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