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Two events A and B are such that P(B) = ...

Two events A and B are such that P(B) = 0 . 55 and P(AB') = 0 . 15 . The probability of occurence of at least one of event is

A

`0.70`

B

`0.20`

C

`0.35`

D

`0.30`

Text Solution

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The correct Answer is:
To find the probability of the occurrence of at least one of the events A or B, we can follow these steps: ### Step-by-Step Solution: 1. **Identify Given Values**: - We are given \( P(B) = 0.55 \) - We are also given \( P(A \cap B') = 0.15 \) 2. **Understand the Events**: - \( P(A \cap B') \) represents the probability of event A occurring while event B does not occur. 3. **Use the Formula**: - We know that the probability of event A can be expressed as: \[ P(A) = P(A \cap B) + P(A \cap B') \] - However, we do not have \( P(A \cap B) \) directly, but we can express \( P(A) \) in terms of \( P(B) \) and \( P(A \cap B') \). 4. **Express \( P(A) \)**: - From the total probability, we can derive: \[ P(A) = P(B) + P(A \cap B') \] - This is based on the idea that the total probability of A can be split into two parts: when B occurs and when B does not occur. 5. **Substitute the Values**: - Substitute the known probabilities into the equation: \[ P(A) = 0.55 + 0.15 \] 6. **Calculate \( P(A) \)**: - Adding these values gives: \[ P(A) = 0.70 \] 7. **Find the Probability of At Least One Event**: - The probability of at least one of the events A or B occurring is given by: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] - However, since we do not have \( P(A \cap B) \), we can use the fact that: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] - But since we need \( P(A \cup B) \) directly, we can also consider that: \[ P(A \cup B) = P(B) + P(A \cap B') \] - Therefore: \[ P(A \cup B) = 0.55 + 0.15 = 0.70 \] 8. **Final Result**: - Thus, the probability of occurrence of at least one of the events A or B is: \[ P(A \cup B) = 0.70 \] ### Conclusion: The probability of occurrence of at least one of event A or B is \( 0.70 \).
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