Show that the circles given by the following equation intersect each other orthogonally.
`x^2 + y^2 - 2x - 2y - 7 = 0,`
` 3x^2 + 3y^2 - 8x + 29y = 0 `.

Show that the circles given by the following equation intersect each other orthogonally. x^2 + y^2 - 2x + 4y + 4 = 0, x^2 + y^2 + 3x + 4y + 1 =0.

Show that the circles given by the following equations intersect each other orthogonally . x^2+y^2+2x-2y=0 x^2+y^2+2x + 2y=0

Show that the circles given by the following equations intersect each other orthogonally . x^2+y^2+4x-2y-11=0 x^2+y^2-4x-8y+11=0

Find the equation of the circle which passes through the origin and intersects each of the following circles orthogonally. x^2+y^2-4x-6y-3=0 x^2+y^2-8y+12=0

The equation of the circle passing through the point of intersection of the circles x^2 + y^2 - 6x + 2y + 4 = 0 and x^2 + y^2 + 2x - 6y - 6=0 and having its centre on y=0 is : (A) 2x^2 + 2y^2 + 8x + 3 = 0 (B) 2x^2 + 2y^2 - 8x - 3 = 0 (C) 2x^2 + 2y^2 - 8x + 3 = 0 (D) none of these

Find k if the following pairs of circles are orthogonal x^2+y^2-6x-8y+12=0 x^2+y^2-4x+6y+k=0

Find k if the following pairs of circles are orthogonal x^2+y^2-6x-8y+12=0 x^2+y^2-4x+6y+k=0

Show that the circles x^2 + y^2 - 2x-6y-12=0 and x^2 + y^2 + 6x+4y-6=0 cut each other orthogonally.

The equation (s) of common tangents (s) to the two circles x^(2) + y^(2) + 4x - 2y + 4 = 0 and x^(2) + y^(2) + 8x - 6y + 24 = 0 is/are

{:(3x - y - 2 - 0),(2x + y - 8 = 0):}