Find the equation of the circle which cu...

Find the equation of the circle which cuts orthogonally the circle `x^(2)+y^(2)-6x+4y-3=0`, passes through (3,0) and touches the axis of y.

Verified by Experts

The correct Answer is:

`x^2+y^2-6x-6y+9=0`

Similar Questions

Explore conceptually related problems

Find the equation of the circle which cuts orthogonally the circle x^2+y^2-6x+4y-12=0 and having the centre at (-1,2).

Find the equation of the circle which cuts orthogonally the circle x^2+y^2-4x+2y-7=0 and having the centre at (2,3)

The loucs of the centre of the circle which cuts orthogonally the circle x^(2)+y^(2)-20x+4=0 and which touches x=2 is

Find the equation of the circle which is concentric with the circle x^2 +y^2 - 4x+6y-3=0 and the double of its area.

The equation of the diameter of the circle x^(2) + y^(2) - 6x + 2y = 0 which passes through origin is

Find the equation of the circle which is concentric with x^(2)+y^(2)+8x+12y+15=0 and passing through (2,3).

Find the equation of the circle concentric with the circle x^2 +y^2 - 4x - 6y-9=0 and passing through the point (-4, -5)

Find the equation of the circle concentric with the circle x^(2) + y^(2) - 8x + 6y -5 = 0 and passing through the point (-2, -7).

Find the equations of the two circles which intersect the circles x^(2)+y^(2)-6y+1=0andx^(2)+y^(2)-4y+1=0 orthogonally and touch the line 3x+4y+5=0 .

Equation of the diameter of the circle x^(2) +y^(2) - 2x + 4y = 0 which passes through the origin is