Prove that the two circles which pass through the points (0,a),(0,-a) and touch the line y=mx+c will cut orthogonally if `c^2=a^2(2+m^2)`

The two circles which pass through (0,a)a n d(0,-a) and touch the line y=m x+c will intersect each other at right angle if (A) a^2=c^2(2m+1) (B) a^2=c^2(2+m^2) (C) c^2=a^2(2+m^2) (D) c^2=a^2(2m+1)

The centre of the circle passing through the points (0,0), (1,0) and touching the circle x^2+y^2=9 is

The circle passing through the points (-2, 5), (0, 0) and intersecting x^2+y^2-4x+3y-2=0 orthogonally is

Find the equations of the circles passing through the point (-4,3) and touching the lines x+y=2 and x-y=2

Find the equations of the circles passing through the point (-4,3) and touching the lines x+y=2 and x-y=2

Find the equation of the circle passing through the point ( 2, 3) and touching the line 2x+3y=4 at the point ( 2, 0)

The circle passing through the point (-1,0) and touching the y-axis at (0,2) also passes through the point:

The circle through the two points (-2,5),(0,0) and intersecting x^2+y^2-4x+3y-1=0 orthogonally is

If the curve y=ax^(2)+bx+c passes through the point (1, 2) and the line y = x touches it at the origin, then

The locus of centres of all circles which touch the line x = 2a and cut the circle x^2 + y^2 = a^2 orthogonally is