If the circle x^2 +y^2 + 2x+2ky+6=0, x^2...

If the circle `x^2 +y^2 + 2x+2ky+6=0, x^2 + y^2 + 2ky+k=0` intersect orthogonally, then `k` is: (A) `2 ` or `-3/2` (B) `-2` or `- 3/2` (C) `2` or `3/2` (D) `-2` or `3/2`

A

4

B

3

C

2

D

1

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The correct Answer is:

D

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