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The equation of the circle which pass th...

The equation of the circle which pass through the origin and cuts orthogonally each of the circles `x^2+y^2-6x+8=0` and `x^2+y^2-2x-2y=7` is

A

`3x^2+3y^2-8x-13y=0`

B

`3x^2+3y^2-8x+29y=0`

C

`3x^2+3y^2+8x+29y=0`

D

`3x^2+3y^2-8x-29y=0`

Text Solution

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The correct Answer is:
B
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