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A line 'I' meets the circle x^2 + y^2 =6...

A line 'I' meets the circle `x^2 + y^2 =61` in A, B and P(-5, 6) is such that PA = PB = 10. Then the equation of 'l' is

A

5x+6y+11=0

B

5x-6y-11=0

C

5x-6y+11=0

D

5x-6y+12=0

Text Solution

Verified by Experts

The correct Answer is:
C
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